• Para reduzir os requisitos de armazenamento.
• Para melhorar a velocidade de transferência em conexões padrão.

1. Extraindo um arquivo zip

# importing required modules from zipfile import ZipFile # specifying the zip file name file_name = 'my_python_files.zip' # opening the zip file in READ mode with ZipFile(file_name 'r') as zip: # printing all the contents of the zip file zip.printdir() # extracting all the files print('Extracting all the files now...') zip.extractall() print('Done!') 

• from zipfile import ZipFile

  ZipFile is a class of zipfile module for reading and writing zip files. Here we import only class ZipFile from zipfile module.

• with ZipFile(file_name 'r') as zip:

  Here a ZipFile object is made by calling ZipFile constructor which accepts zip file name and mode parameters. We create a ZipFile object in LER modo e nomeá-lo como zip .

• zip.printdir()

  imprimirdir() O método imprime um índice para o arquivo.

• zip.extractall()

  extrair tudo() O método extrairá todo o conteúdo do arquivo zip para o diretório de trabalho atual. Você também pode ligar extrair() method to extract any file by specifying its path in the zip file. For example:

  zip.extract('python_files/python_wiki.txt')

  This will extract only the specified file. If you want to read some specific file you can go like this:

  data = zip.read(name_of_file_to_read)

2. Gravando em um arquivo zip

# importing required modules from zipfile import ZipFile import os def get_all_file_paths(directory): # initializing empty file paths list file_paths = [] # crawling through directory and subdirectories for root directories files in os.walk(directory): for filename in files: # join the two strings in order to form the full filepath. filepath = os.path.join(root filename) file_paths.append(filepath) # returning all file paths return file_paths def main(): # path to folder which needs to be zipped directory = './python_files' # calling function to get all file paths in the directory file_paths = get_all_file_paths(directory) # printing the list of all files to be zipped print('Following files will be zipped:') for file_name in file_paths: print(file_name) # writing files to a zipfile with ZipFile('my_python_files.zip''w') as zip: # writing each file one by one for file in file_paths: zip.write(file) print('All files zipped successfully!') if __name__ == '__main__': main() 

• def get_all_file_paths(directory): file_paths = [] for root directories files in os.walk(directory): for filename in files: filepath = os.path.join(root filename) file_paths.append(filepath) return file_paths

  First of all to get all file paths in our directory we have created this function which uses the os.walk()  método. Em cada iteração, todos os arquivos presentes naquele diretório são anexados a uma lista chamada caminhos_de_arquivos . No final retornamos todos os caminhos dos arquivos.

• file_paths = get_all_file_paths(directory)

  Here we pass the directory to be zipped to the get_all_file_paths() função e obter uma lista contendo todos os caminhos de arquivo.

• with ZipFile('my_python_files.zip''w') as zip:

  Here we create a ZipFile object in WRITE mode this time.

• for file in file_paths: zip.write(file)

  Here we write all the files to the zip file one by one using escrever método.

3. Obtendo todas as informações sobre um arquivo zip

# importing required modules from zipfile import ZipFile import datetime # specifying the zip file name file_name = 'example.zip' # opening the zip file in READ mode with ZipFile(file_name 'r') as zip: for info in zip.infolist(): print(info.filename) print('tModified:t' + str(datetime.datetime(*info.date_time))) print('tSystem:tt' + str(info.create_system) + '(0 = Windows 3 = Unix)') print('tZIP version:t' + str(info.create_version)) print('tCompressed:t' + str(info.compress_size) + ' bytes') print('tUncompressed:t' + str(info.file_size) + ' bytes') 

for info in zip.infolist():